Question 3326
{{{(5y^3-8y^2-32y+21)/(y^2-y-7)}}}


I can see no easy factorisation here, so we need to try long division of {{{5y^3-8y^2-32y+21}}} by {{{y^2-y-7}}}.


Doing this, gives a precise division of 5y-3 with no remainder.


jon.