Question 201638
The product of two consecutive even integers is 28 less than the square of larger number. Find the two integers.
I've written:{{{x+x+2=(x+2)^2-28}}}
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You have the sum on the left side, not the product.
{{{x*(x+2) = (x+2)^2 - 28}}}
{{{x^2+2x = x^2+4x+4 - 28}}}
2x = 24
x = 12
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The numbers are 12 and 14.