Question 27841
To graph these, first get the equations into the slope-intercept form: y = mx + b

1) {{{x-5y = -30}}} is {{{y = (1/5)x+6}}}
2) {{{2x-y = 3}}} is {{{y = 2x-3}}}

Now you can graph them:
{{{graph(300,200,-35,8,-5,8,(1/5)x+6,2x-3)}}}
It's a little hard to read from the graph, but the point of intersection (solution) is: (5, 7)