Question 201586
Is the function {{{log(2,(x+7))}}} ????


If so, then simply shift the graph of {{{log(2,(x))}}} 7 units to the left to get the graph of {{{log(2,(x+7))}}}



Here are the graphs:


{{{ drawing(500, 500, -10, 10, -10, 10,
 graph( 500, 500, -10, 10, -10, 10,log(2,(x)),log(2,(x+7)))

)}}}


Graph of {{{y=log(2,(x))}}} (red) and {{{y=log(2,(x+7))}}} (green)



-----------------------


OR...


Is the function {{{log(2,(x))+7}}} ????


If so, then simply shift the graph of {{{log(2,(x))}}} 7 units up to get the graph of {{{log(2,(x))+7}}}




Here are the graphs:


{{{ drawing(500, 500, -10, 10, -10, 10,
 graph( 500, 500, -10, 10, -10, 10,log(2,(x)),log(2,(x))+7)

)}}}


Graph of {{{y=log(2,(x))}}} (red) and {{{y=log(2,(x))+7}}} (green)