Question 201560
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Just substitute -3 in place of *[tex \Large x] and do the arithmetic.  But since you are given 4 answers, let's look at them.  They are all *[tex \Large \frac{\sqrt{10}}{-4}].  Since *[tex \Large \sqrt{10}] is positive (by convention -- the negative square root would be designated *[tex \Large -\sqrt{10}]), and the denominator is clearly negative, the quotient must be negative.  Goodbye Answer B.


If it were Answer C, then *[tex \Large \sqrt{10}] would have to be equal to 100.  Since we know that *[tex \Large \sqrt{10}] is less than 10, that can't be true.  Goodbye, Answer C.


If it is Answer D, then *[tex \Large \sqrt{10}] has to be larger than 4, but if it is Answer A, then *[tex \Large \sqrt{10}] has to be smaller than 4.  We know that 3 times 3 equals 9, so 3 is smaller than the square root of 10, but 4 times 4 is 16, so 4 is larger than the square root of 10.


And I never touched a calculator...


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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