Question 201507
Apply log rules:
{{{log(2,x)+log(2,(x+2))=3}}}
{{{log(2,x(x+2))=3}}}
{{{x(x+2)= 2^3}}}
{{{x^2+2x= 8}}}
{{{x^2+2x-8=0}}}
{{{(x+4)(x-2)=0}}}
.
x = {-4, 2}
We can throw out the negative solution leaving:
x = {2}