Question 201467
 If Javier has a handful of of coins consisting of dimes,nickles and pennies making a total of 2.63 how much of each coin does he have?
The amount of nickles is 1 less than twice of pennies --> n = 2p-1
The amount of dimes is 3 more the amount of nickels --> d = n + 3
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10d + 5n + p = 263
n = 2p - 1
d = n + 3
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d = n+3 = 2p+2
Sub for d and n in the 1st eqn
10(2p+2) + 5(2p-1) + p = 263
31p + 15 = 263
31p = 248
p = 8
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n = 15
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d = 18