Question 201439
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If "C" had one-third of what was left after "B" was done, then 8 must be two-thirds of what was left after "B" was done, so the number left after "B" was done is 8 divided by *[tex \Large \frac{2}{3}] or *[tex \Large 8 \times \frac{3}{2} = 12].  Likewise, the number left after "A" was done is *[tex \Large 12 \times \frac{3}{2} = 18].  And finally, the number that was there at the start was *[tex \Large 18 \times \frac{3}{2} = 27].    


John
*[tex \Large e^{i\pi} + 1 = 0]
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