Question 201352
1) You are given the equation for a line. {{{x-4y=6}}}
Every point on a line is in the form (x , y).
You are given a y value {{{y = 1/4}}} and asked to find the x value that results in a point on the given line
So, Substitute the given value for y into the given equation and then solve for x
{{{x-4y=6}}}
{{{x-4*(1/4)=6}}}
{{{x-1=6}}}
{{{x = 7}}}
So one point is (7, 1/4)

Next you are given an x value {{{x = -2}}} and asked to find the y value that results in a point on the given line.
{{{x-4y=6}}}
{{{-2 -4y = 6}}}
{{{-4y = 8}}}
{{{y = -2}}}
So another point is given by (-2, -2)

2){{{7x + y = 8}}}
You are asked to find the slope and the y intercept. One form of the equation for a line is called the slope/intercept form. It is in the form {{{y = mx + b}}}
where m is the slope and b is the y intercept. So all we need to do is transform the given equation into the slope intercept form
{{{7x + y = 8}}}
{{{y = -7x + 8}}}
which is in the correct form
m=-7 (slope is -7) 
b is 8. So the y intercept is the point (0,8)