Question 27820
Because all of the sides are "consecutive odd integers" the 3 sides can be written as x, x+2, and x+4.  (Example, if the first one was 7, the second would be 7+2=9, and the third would be 7+4=11).
We're told that the perimeter is 207, so that means all three must add up to 207.  Write this as:
{{{(x)+(x+2)+(x+4)=207}}}
{{{3x+6=207}}}
{{{3x=201}}}
{{{x=67}}}
The three sides are 67, 69, and 71.
{{{67+69+71=207}}}Check.