Question 201309
I believe you mean: (correct me if I'm wrong)
.
{{{ 6/(a^2-3a-54) + 10/(a^2+5a-6)}}}
.
Factoring the denominators we get:
{{{ 6/((a-9)(a+6)) + 10/((a+6)(a-1))}}}
.
Now, find common denominator: (a-9)(a+6)(a-1)
and convert each term to have the same denominator:
{{{ 6(a-1)/((a-9)(a+6)(a-1)) + 10(a-9)/((a-9)(a+6)(a-1))}}}
.
Combining the two terms:
{{{ (6(a-1) + 10(a-9))/((a-9)(a+6)(a-1))}}}
.
{{{ (6a-6 + 10a-90)/((a-9)(a+6)(a-1))}}}
{{{ (16a-96)/((a-9)(a+6)(a-1))}}}
.
Factoring the numerator:
{{{ 16(a-6)/((a-9)(a+6)(a-1))}}}