Question 201289
Let s=length of a side and A=area
s^2=A
when s=1 then area=1
when s=sqrt(6) the area=6
The length of the diagonals can be found using a^2+b^2=c^2
1+1=2
diagonal =sqrt(2)
6+6=12
diagonal = sqrt(12)
=sqrt(4*3)
=2sqrt(3)
The ratio of the lengths of the diagonals is 2sqrt(3):sqrt(2)
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Ed