Question 201231
If the values "m" and "n" are the solutions to an equation of the form {{{ax^2+bx+c=0}}}, then the x-intercepts of {{{f(x)=ax^2+bx+c}}} are (m,0) and (n,0)



So in your case, the solutions are x=0 or x=-2 which means that the x-intercepts are (0,0) and (-2,0)