Question 201232
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If the pages are two facing pages, presuming that no one ripped a page out of the book, the numbers must be consecutive, that is to say the larger one is one larger than the smaller.  So, let *[tex \Large x] represent the left-hand page, then *[tex \Large x + 1] must be the right hand page.


Further, we are given that the product of the two page numbers is 1482, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x(x + 1) = 1482]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2 + x - 1482 = 0]


Just solve the quadratic and exclude the negative root.  Hint:  It factors.  Since the factors of 1482 must differ by only 1, I would start looking for factors in the neighborhood of the integer part of the square root of 1482.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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