Question 201226
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The first number in your ordered pair is the *[tex \Large x]-coordinate of the point and the second number is the *[tex \Large y]-coordinate.  Substitute the value of the *[tex \Large x]-coordinate for *[tex \Large x] in your equation and Substitute the value of the *[tex \Large y]-coordinate for *[tex \Large y]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2 + y^2 - 8x + 6y = -21]



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (4)^2 + (-1)^2 - 8(4) + 6(-1) =^? -21]


Do the arithmetic.  If the result is a true statement, then your answer is yes, the given point is on the graph.  Otherwise the answer is no.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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