Question 201192
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y = ax^2 + bx + c]


where *[tex \Large x = 1] and *[tex \Large y = 359]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a + b + c = 359]


and where *[tex \Large x = 3] and *[tex \Large y = 281]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 9a + 3b + c = 281]


and where *[tex \Large x = 4] and *[tex \Large y = 194]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 16a + 4b + c = 194]


Now you have 3 linear equations in *[tex \Large a], *[tex \Large b], and *[tex \Large c].  Solve the system for your set of three coefficients.


Once you have your three coefficients, substitute them into


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y = ax^2 + bx + c]


Then substitute 5 for *[tex \Large x] and do the arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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