Question 201205
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{200000}{x}]


is the amount it will cost each person before they find the five new members.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{200000}{x + 5}]


is the amount that each person will pay if they add 5 members.


These two amounts differ by $2,000, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{200000}{x + 5} + 2000 = \frac{200000}{x}]


Just solve for *[tex \Large x].  Hint: I would start by multiplying both sides of this equation by *[tex \Large \frac{1}{2000}].  You will end up solving a quadratic.  Remember to exclude the negative root.  Having a negative number of members doesn't make sense.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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