Question 201203
{{{x^2-12x+36=25}}} Start with the given equation.



{{{x^2-12x+36-25=0}}} Get all terms to the left side.



{{{x^2-12x+11=0}}} Combine like terms.



{{{(x-11)(x-1)=0}}} Factor the left side 



Now set each factor equal to zero:

{{{x-11=0}}} or  {{{x-1=0}}} 



{{{x=11}}} or  {{{x=1}}}    Now solve for x in each case



So the answers are 


 {{{x=11}}} or  {{{x=1}}}