Question 201211
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^{\frac{1}{n}} = \sqrt[n]{a}]


also


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a^{\frac{m}{n}} = \sqrt[n]{a^m} = (\sqrt[n]{a})^m]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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