Question 201182
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You didn't provide the function, so all I can do is tell you to take the number in the parentheses and substitute it for *[tex \Large x] in your function and then do the arithmetic.  Remember *[tex \Large g] is the function, *[tex \Large g(x)] is the <b><i>value</i></b> of the function at *[tex \Large x].  Therefore *[tex \Large g(-4)] is the value of the function *[tex \Large g] when *[tex \Large x = -4]


The domain of a function is the set of allowable values.  It could be all real numbers (as in the case of a polynomial function: *[tex \Large f(x) = a_0x^n + a_1x^{n-1} +\ \cdots\ + a_{n-1}x + a_n]), all real numbers excluding values that would make a denominator be zero (such as: *[tex \Large f(x) = \frac{g(x)}{h(x)} ] where *[tex \Large g(x)] and *[tex \Large h(x)] are polynomial functions, then the domain of *[tex \Large f] would be all real numbers except those number(s) that would make *[tex \Large h(x) = 0]), *[tex \Large \sqrt{x}] is restricted to *[tex \Large x \geq 0], *[tex \Large \ln(x)] is restricted to *[tex \Large x > 0].  This is not an all inclusive list by any means.


The range of a function is the set of possible outputs.  A linear function (y = mx + b]) has all real numbers for a range.  A parabola of the form *[tex \Large y = ax^2 + bx + c] has either a minimum or maximum value (depending on which way it opens) and that would be one endpoint of the range.  *[tex \Large \ln(x)] has a range of all real numbers, while *[tex \Large \sqrt{x}] has a range identical to its domain.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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