Question 201169
y = x^2 +6x+10
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To  find  x  intercepts, set  y=0,,and  solve  eqn
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x^2 +6x+10 =0
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Using  quadratic  eqn  to  factor
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a=1,,,b=6,,,c=10
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x=[ -(6) +/- sqrt (6^2 -4(1)(10)] /2 (1)
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x=[-6 +/- sqrt (-4) ] /2
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x= -3 +/- 2i,,,,,,,or  no  real  number  intercepts
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further  review  shows  an  upward  pointing  y  parabola,,,with  vertex  at (-3,1)