Question 201130
    A rectangular swimming pool is 2 m longer than it is wide. If the width is decreased by 3 m, and the length is increased by 4 m, the area remains the same as the original area, Find the original dimensions of the pool. 
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Let w = width of pool
then
w+2 = length of pool
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(w-3)(w+2 +4) = w(w+2)
(w-3)(w+6) = w(w+2)
w^2+6w-3w-19 = w^2+2w
w^2+3w-19 = w^2+2w
3w-19 = 2w
w-19 = 0
w = 19 m (width of pool)
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Length:
w+2 = 19+2 = 21 m (length of pool)
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Dimensions: 19m x 21m