Question 201102
Solve the following equation by using the quadratic formula:
p^2 + 8p + 16 = 0 
---
p = [-8 +- sqrt(64 - 4*1*16)]/2
p = [-8 +- sqrt(0)]/2
p = -8/2 = -4 with multiplicty 2.
==============================================


Find the perfect square trinomial whose first two terms are:
a^2 - 4a. 
a^2 - 4a + (2)^2
(a-2)^2
==============================================

Determine the vertex and the axis of symmetry of the given quadratic.
y = ¼x^2 - x + 5 
Vertex occurs when x = -b/2a = 1/(1/2) = 2
-------
f(2) = 4
Vertex at (2,4)
====================================
Cheers,
Stan H.