Question 201018
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*[tex \Large \forall x \in I,\ \ \sqrt{x}] is rational if and only if *[tex \Large \exists p \in I] such that *[tex \Large x = p^2]


In other words, if your radicand is an integer, then the square root is not rational unless there is some integer if squared is equal to the radicand.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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