Question 200957
Factor completely:
{{{x^5y^3-3x^4y^2-28x^3y}}} First factor out {{{x^3y}}}
{{{(x^3y)(x^2y^2-3xy-28)}}} Now factor the trinomial in the 2nd parentheses.
{{{highlight((x^3y)(xy+4)(xy-7))}}}