Question 200941
Rationalize the denominator: 
3x divided by index 5 root of 2x^2y^3. They say answer is 3 times index 5 root of 16x^3y^2 divided by 2y
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Rewrite the problem as:
(3x)/(2x^2y^3)^(1/5)
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Multiply numerator and denominator by 2^(4)*x^(3)*y^(2) to get:
{(3x)[2^(4)*x^(3)*y^(2)]^(1/5)/[2^5*x^5*y^5]^(1/5)
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Simplify:
{(3x)[(2^(4)*x^(3)*y^(2)]^(1/5)/[2xy]
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Cancel the "x" factor to get:
= [3[(2^(4)*x^(3)*y^(2)]^(1/5)/[2y]
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Cheers,
Stan H.