<PRE><B>Question 200905</B>
f(x)=x^2-9/x^2 / x^5+3x^4/x+2
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Factor where you can to get:
f(x)=[(x-3)(x+3)]/x^2 / [x^4(x+3)]/(x+2)
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Invert the denominator and change to multiplication:
= [[(x-3)(x+3)]/x^2] *[(x+2)/[x^4(x+3)]]
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Cancel all factors common to a numerator and a denominator to get:
= [[(x-3)]/1] *[(x+2)/[x^2]]
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Simplify:
= [(x-3)(x+2)]/[x^2]
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Cheers,
Stan H.

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