<PRE><B>Question 27739</B>
Factor:
{{{2x^3y^2-32xy^2}}}
First, look for common factors in the two terms and factor them out.
2 is a common factor.
x is a common factor,
y^2 is a common factor.

{{{2xy^2(x^2-16)}}} The parentheses now contain a binomial which, as you can see, is the difference of two squares (x-squared and 4-squared) and this binomial can be factored:
{{{x^2-16 = (x-4)(x+4)}}} The final result is:
{{{2x^3y^2-32xy^2 = 2xy^2(x-4)(x+4)}}}</PRE>