Question 200850
(1)  4a +3b =27
(2) 3a +4b = 29
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multiply  (1) by 3,,,,and  (2) by 4
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(3) 12a +9b = 81
(4) 12a +16b = 116
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(4) - (3) 
7b = 35
b=5
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subst  into (1)
4a +3(5) = 27
4a =12
a=3
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check
(1) 4(3) +3(5) = 27,,,,,12 +15 =27 ,,,,,,ok
(2) 3(3) +4(5) =29,,,,9+20=29,,,,,,,ok
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subst  into  7a + 7b/2 = 7(3) +7(5) /2 = 21 + 35/2 = 38.5
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or  subst (7a +7b )/2 = (7*3 +7*5)/2= 56 /2 =28