Question 200813
Applying the substitution method:
x-y=5   (equation 1)
3x+y=3  (equation 2)
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Solve equation 1 for x:
x-y=5
x = y+5
Substitute the above into equation 2 and solve for y:
3x+y=3
3(y+5)+y=3
3y+15+y=3
4y+15=3
4y = -12
y = -3
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Substitute the above into equation 1 and solve for x:
x-y=5
x-(-3)=5
x+3 = 5
x = 2
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Solution:
x=2 and y=-3