Question 200800
{{{(2x-y^2)/(x-y)}}} Start with the given expression.



{{{(2(10)-(-5)^2)/(10-(-5))}}} Plug in {{{x=10}}} and {{{y=-5}}}



{{{(2(10)-(-5)^2)/(10+5)}}} Rewrite {{{10-(-5)}}} as {{{10+5}}}



{{{(2(10)-25)/(10+5)}}} Square -5 to get 25



{{{(20-25)/(10+5)}}} Multiply



{{{(-5)/(15)}}} Combine like terms.



{{{-1/3}}} Reduce



So {{{(2x-y^2)/(x-y)=-1/3}}} when {{{x=10}}} and {{{y=-5}}}



So either you entered the problem in wrong or there's a typo somewhere in your book. Is there something missing? Repost with the clarifications.