Question 200792
x^2+(x+2)^2=(10)^2
2x^2+4x-96=0
a=2 b=4 c=-96
b^2-4(2)(-96)=768

Sq root of 768=28
x=(-4+or-28)/4
x=(-4+28)/4=6
w=6
l=w+2=8