Question 200776
(-5,3) and (5,-3)
First we need to find the slope (m) in the line equation Y=mX+b.
m=(y2-y1)/(x2-x1)
m=(-3-3)/(5+5)=-6/10 is the slope.
Now replacing the X+Y terms with one set of X & Y values we solve for the Y intercept (b).
3=-6/10*-5+b
3=30/10+b
b=3-30/10
b=3-3
b=0 which is the Y intercept.
Y=-6x/10 is the line equation which runs through the points (-5,3) & (5,-3).
Proof:
{{{ graph( 300, 200, -6, 5, -10, 10, y = -6x/10 ) }}} (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -6x/10).