Question 200709
2000 seats in 3 cats 3/5 sold for 7 days
A=x
B=x+600
C=2x
 x+x+600+2x=2000
4x+600=2000
4x=1400
x=350 seats

A=x=350(.6)=210
B=x+600=950
C=2x=700

prices
a=35(2)=70
b=20+15=35
c=20

A=350(.6)=210(70)=$14700
B=950(.6)=570(35)=$19950
C=700(.6)=420(20)=$ 8400
total sales      =$43050(7 days)=$301350