Question 200668
Let's start on the left side and manipulate the logs to get something a little less cluttered
{{{ 2log(x+y)=logx+logy+4log2}}}
{{{ log((x+y)^2)=log((xy2^4))}}}
{{{(x+y)^2 = 16xy}}}
{{{x^2 + 2xy + y^2 = 16xy}}}
{{{x^2 + y^2 = 14xy}}}