Question 200595


{{{(x^3+5x^2)/(2x^2+9x-5)}}} Start with the given expression.



{{{(x^2(x+5))/(2x^2+9x-5)}}} Factor {{{x^3+5x^2}}} to get {{{x^2(x+5)}}}.



{{{(x^2(x+5))/((x+5)(2x-1))}}} Factor {{{2x^2+9x-5}}} to get {{{(x+5)(2x-1)}}}.



{{{(x^2*highlight((x+5)))/(highlight((x+5))(2x-1))}}} Highlight the common terms. 



{{{(x^2*cross((x+5)))/(cross((x+5))(2x-1))}}} Cancel out the common terms. 



{{{(x^2)/(2x-1)}}} Simplify. 



So {{{(x^3+5x^2)/(2x^2+9x-5)}}} simplifies to {{{(x^2)/(2x-1)}}}.



In other words, {{{(x^3+5x^2)/(2x^2+9x-5)=(x^2)/(2x-1)}}} where {{{x<>-5}}} or {{{x<>1/2}}}