Question 27648
First you need to put the equation in slope-intercept form;
3x+2y=8
2y=-3x+8
y=-{{{3/2}}}y+4
Now a line that is parallel to this line is going to have the same slope,which is;
-{{{3/2}}}
So your equation will begn by;
y=-{{{3/2}}}x+b
Now we need to find the y-intercept, so with the point given you fill in the equation;
y-y1=-{{{3/2}}}(x-x1)
y-2=-{{{3/2}}}(x-6)
y-2=-{{{3/2}}}x+{{{18/2}}}
y-2=-{{{3/2}}}x+9
y=-{{{3/2}}}x+11
Hope you understand
=)