Question 200477
{{{log(8,(2))=(log(10,(2)))/(log(10,(8)))=(log(10,(2)))/(log(10,(2^3)))=(log(10,(2)))/(3*log(10,(2)))=(cross(log(10,(2))))/(3*cross(log(10,(2))))=1/3}}}



So {{{log(8,(2))=1/3}}}