Question 200433
16 x^(4/5) * 8x^(3/4)
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remember,,,,,a^m*a^n = a^(m+n),,,,,,and  a^m /a^n =a^(m-n)
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Combine  like  terms
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16*8*x^(4/5) *x^(3/4) 
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128 x^( 4/5 +3/4),,,,,,,,,,,,,,,,,,,,4/5 +3/4 = (16 +15)/20 = 31 /20
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128x^( 31/20)
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2x ( 64) x^{  ( 31/20 - (20/20)  },,,,,,,,,,,,,,20/20 =1,,,,,x^1=x
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2x( 64x^(11/20)  )
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Checking
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Let  x=2,,,,original  =  374.8,,,,,answer = 274.8,,,,,ok