Question 200402
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The equation for a circle centered at *[tex \Large (h,k)] with radius *[tex \Large r] is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x - h)^2 + (y - k)^2 = r^2]


So your circle has a center at (0,0) and a radius of the square root of 64.


The diameter of a circle is twice the radius, and the area is *[tex \Large \pi] times the radius squared.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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