Question 200346
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Given:  R=1500x–3x^2, where{{{system(R=Revenue, x=pools)}}}


If R = $17,568,
{{{17568=1500x-3x^2}}}


Isolate all figures to the left, equating to zero: (change signs)
{{{3x^2-1500x+17568=0}}}


Divide all figures by "3":
{{{x^2-500x+5856=0}}}


By Quadraric where{{{system(a=1,b=-500,c=5856)}}}


Solving discriminant: {{{b^2-4ac=-500^2-4(1)(5856)=250000-11424=250000-23424=red(226576)}}}


Then,
{{{x=(-(-500)+-sqrt(226576))/(2(1))=(500+-476)/2}}}
{{{x=(500+476)/2=976/2=488}}}
Also, {{{x=(500-476)/2=24/2=highlight(red(12))}}}, Answer (less than 25 pools)


Check,
{{{R=1500(x)-3x^2}}}
{{{17568=1500(12)-3(12)^2}}}
{{{17568=18000-432}}}
{{{17568=17568}}}


Thank you,
Jojo</font>