Question 200358
Question 1. Find the equation of the line that passes through the point (-2,5) and parallel to the y axis.
x = -2
.
Question 2. Find the equation of the line passing through (1,3) and parallel to the line y = 3/2 x - 1/2.
If a two lines are parallel, the slopes are the same.
Our line has a slope of 3/2 crossing (1,3)
plug into point-slope form
y-y1 = m(x-x1)
y-3 = (3/2)(x-1)
y-3 = (3/2)x - 3/2
y = (3/2)x - 3/2 + 3
y = (3/2)x - 3/2 + 6/2
y = (3/2)x + 3/2
.
Question 3. A line with the gradient 2 passes through the point (1,3). Find the equation of the line.
Gradient is equivalent to the slope
So m = 2 and it crosses (1,3)
plug into point-slope form
y-y1 = m(x-x1)
y-3 = 2(x-1)
y-3 = 2x-2
y = 2x + 1