Question 200335
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Exactly correct.  Think about it this way:  If you have already rolled a 5, there are exactly six possible outcomes for the sum of the two upward faces, 5 + 1 = 6, 5 + 2 = 7, 5 + 3 = 8, 5 + 4 = 9, 5 + 5 = 10, and 5 + 6 = 11.  Only one of those combinations is 8, so only one result out of six possibilities represents success.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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