Question 200271
n^2+3(n)=24 
n^2+3n-24=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(-3+-sqrt[3^2-4*1*-24])/2*1
x=(-3+-sqrt[9+96])/2
x=(-3+-sqrt105)/2
x=(-3+-10.247)/2
x=(-3+10.247)/2
x=7.247/2
x=3.6235 ans.
x=(-2-10.247)/2
x=-12.247/2
x=-6.1235 ans.