Question 200244
{{{(2y+1)/(y^2-y-6)}}}
Which y is disallowed? Any y that results in the denominator becoming 0
Which y make the denominator 0?
{{{y^2 - y - 6 = 0}}}
{{{(y-3)(y+2) = 0}}}
So y = 3 and y =-2 cannot be used (not in the domain)