Question 200198
x^2-2x-13=0
Using the quadratic equation:{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} We get:
x=(2+-sqrt[-2^2-4*1*-13])/2*1
x=(2+-sqrt[4+52)/2
x=(2+-sqrt56)/2
x=(2+-7.48)/2
x=(2+7.48)/2
x=9.48/2
x=4.74 ans.
x=(2-9.48)/2
x=-7.48/2
x=-3/74 ans.