Question 200179
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The area of a triangle in terms of the measure of the base and the height is:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A = \frac{bh}{2}]


You know the area and the measure of the base, so substitute those values:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 27 = \frac{9h}{2}]


Just solve for *[tex \Large h].  Multiply both sides by 2, then divide both sides by 9.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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