Question 200032
Trains A and B are traveling in the same direction on parallel tracks.
 Train A is traveling at 40 mph and train B is traveling at 44 mph.
 Train A passes a station at 5:10 PM.
 If train B passes the same stations at 5:40 PM, what time will train B catch up with train A
:
When train A passes the station, train B is .5 hrs from the station
At 44 mph, we can say; .5*44 = 22 mi is B's dist from Train A at 5:10
:
Let t = time from 5:10 that train B catches train A
:
Write a distance equation; (train B has to travel 22 mi further than train A)
44t = 40t + 22
:
44t - 40t = 22
:
4t = 22
t = {{{22/4}}}
t = 5.5 hrs for Train B to catch Train A
;
The time:
5:10 + 5:30 = 10:40 PM
:
:
Check solution by finding the distance traveled by each
Train B = 44 * 5.5 = 242 mi
Train A = 40 * 5.5 = 220 mi
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difference in dist: = 22 mi