Question 199968
{{{g*f=g(x)*f(x)=(2x-4)*(x^2-3x)=2x^3-10x^2+12x}}}



So {{{g*f=2x^3-10x^2+12x}}}



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{{{f(g(0))=f(2*0-4)=f(-4)=(-4)^2-3(-4)=16+12=28}}}


So {{{f(g(0))=28}}}