Question 199943
{{{log3 (x-2) + log3 (x-4) = 2 }}}
:
Addition of logs, the same as multiply
{{{log3((x-2)*(x-4)) = 2 }}}
FOIL
{{{log3(x^2-6x+8) = 2 }}}
The exponent equiv of logs:
(x^2 - 6x + 8) = 3^2
:
x^2 - 6x + 8 = 9
:
x^2 - 6x + 8 - 9 = 0
:
x^2 - 6x - 1 = 0
:
Use the quadratic formula: a=1; b=-6; c=-1
The positive solution: x ~ 6.162
: